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	<title>H2O2 Therapy Experiments</title>
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	<description>Hydrogenperoxide Therapy - H2O2 -is both old and new. A revolutionary self-healing tool</description>
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		<title>Your Questions About H2o2 Oxidation Number</title>
		<link>http://www.answers-h2o2.com/228/your-questions-about-h2o2-oxidation-number-20/</link>
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		<pubDate>Thu, 19 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Carol asks… help with oxidation and reduction? Im doing some oxidation work for a chem class and i keep getting stuck on questions like these, any help would me much appreciated!!! When the following reaction is balanced in acid solution &#8230; <a href="http://www.answers-h2o2.com/228/your-questions-about-h2o2-oxidation-number-20/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<p class="name">Carol asks…</p>
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<h2>help with oxidation and reduction?</h2>
<p>Im doing some <strong>oxidation</strong> work for a chem class and i keep getting stuck on questions like these, any help would me much appreciated!!!</p>
<p>When the following reaction is balanced in acid solution using the lowest possible whole <strong>number</strong> coefficients, the coefficient of H+ will be:<br />
I2(s) + OCl-(aq) &#8211;&gt; IO3-(aq)+ Cl-(aq)</p>
<p>Balance the following reaction in acidic aqueous solution. What is the coefficient of Mn2+(aq)?<br />
Cu(s) + MnO4-(aq) &#8212;&gt; Cu2+(aq) + Mn2+(aq)</p>
<p>When the following reaction is balanced in basic solution using the lowest possible whole <strong>number</strong> coefficients, the coefficient of H2O will be:<br />
Cl2O7(aq) + <strong>H2O2</strong>(aq) &#8211;&gt; ClO2- (aq) + O2(g)</p>
<p>Complete and balance the following half reaction in acid.<br />
TiO2(s) &#8211;&gt; Ti2+(aq)<br />
How many electrons are needed and is the reaction an <strong>oxidation</strong> or reduction?<br />
1 electron, <strong>oxidation</strong><br />
2 electrons, <strong>oxidation</strong><br />
4 electrons, <strong>oxidation</strong><br />
1 electron, reduction<br />
2 electrons, reduction<br />
4 electrons, reduction</p>
<p>When the following half-reaction, which occurs in acidic solution, is balanced, ___ electrons appear on the ___ side: IO3-(aq) &#8211;&gt; I- (aq)<br />
6, left<br />
5, right<br />
4, left<br />
3, right<br />
2, left</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Balance the following reaction in acidic aqueous solution. What is the coefficient of Mn2+(aq)?<br />
Cu(s) + MnO4-(aq) &#8212;&gt; Cu2+(aq) + Mn2+(aq)</p>
<p>Ans: 2</p>
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<p class="name">Michael asks…</p>
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<h2>Will H2O2 ever be a viable automotive fuel?</h2>
<p>I heard about a car the other day that runs on Hydrogen Peroxide (<strong>H2O2</strong>). Its only emission is water vapor and oxygen, which sounds cool, but then I looked into it a bit more and I don&#8217;t see any viability coming from it and wanted to know what others think of it.</p>
<p>First concern is price. Currently the car in question runs off of a 50% solution! The stuff in the drug stores is only 3%! 50% runs about $120 a gallon which seems really expensive. Also it isn&#8217;t that easily accessible. I would think any fuel station would be expensive to build and that cost would be added to the consumer. <strong>H2O2</strong> is a corrosive agent and can&#8217;t be stored in steel drums IIRC. I know that the most common way to make Hydrogen Peroxide is through the use of electricity. This is really ineffective as you can never get back out all the energy put into it.</p>
<p>Second concern is safety. The emission is not water vapor at the pure form &#8211; it is super heated steam! I could see this causing severe burns if not death to anyone too close to the exhaust. Also with the massive amount of water vapor, I can&#8217;t see any normal exhaust system holding up to the abuse over any <strong>number</strong> of years as most normal exhaust system would just rust away.</p>
<p><strong>H2O2</strong> is widely used in rockets, and even some underwater applications because it doesn&#8217;t require oxygen to produce thrust as its <strong>oxidation</strong> process produces a lot of volume. Even so, it is still very expensive for these uses. With the electric and hybrid cars being more commonplace, is there even a reason to explore the use of <strong>H2O2</strong> in practical everyday automobile use??</p>
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<h3>admin answers:</h3>
<p class="dtm-content">You&#8217;re correct on most points.</p>
<p>Peroxide is expensive, difficult, and inefficient to manufacture. Peroxide is unstable and tends to break down, so you can&#8217;t really stockpile it.</p>
<p>Peroxide is NOT manufactured through electrolysis. It isn&#8217;t an electrochemical reaction; rather it&#8217;s made through a fairly simple (but inefficient) redox reaction.</p>
<p>Almost all peroxide is produced by bubbling compressed air through a solution of 2-ethyl-9,10-dihydroxy-anthracene. This yields 2-ethyl anthraquinone, plus about 60% water versus 40% peroxide (not a very efficient reaction.)  </p>
<p>The water, peroxide, and anthraquinone are separated (by distillation I assume.) The anthraquinone is then regenerated back into the dihydroxy-anthracene by bubbling hydrogen through it in the presence of a metal-based catalyst. The distillation is energy intensive; producing hydrogen to regenerate the dihydroxy-anthracene is also very energy intensive.</p>
<p>There&#8217;s been some research into designing a catalyst to produce it directly from H2 and O2 gases. However under nearly all circumstances thermodynamics favors the production of simple water instead of peroxide, Furthermore catylists researched for this purpose usually end up also enabling the breakdown of any peroxide formed, into O2 and water. </p>
<p>Peroxide is used in select rocket applications.I wouldn&#8217;t say they were &#8220;widely&#8221; used. </p>
<p>Peroxide rockets are useful because they&#8217;re extraordinarily simple and reliable. They use a single propellant, which in of itself is not a fire or explosion hazard. They can be easily throttled. However peroxide rockets have a very low specific impulse compared to other types.  </p>
<p>That&#8217;s what I know.</p>
<p>So basically, NO. </p>
<p>Battery-electric cars are more practical in every possible way.</p>
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		<title>Your Questions About Oxygen Therapy</title>
		<link>http://www.answers-h2o2.com/227/your-questions-about-oxygen-therapy-50/</link>
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		<pubDate>Wed, 18 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Charles asks… How much does an oxygen tank cost? I use ozone therapy and I want to move to another state to live with some friends for a few months, but I don&#8217;t want to have to ship my oxygen &#8230; <a href="http://www.answers-h2o2.com/227/your-questions-about-oxygen-therapy-50/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<p class="name">Charles asks…</p>
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<h2>How much does an oxygen tank cost?</h2>
<p>I use ozone <strong>therapy</strong> and I want to move to another state to live with some friends for a few months, but I don&#8217;t want to have to ship my <strong>oxygen</strong> concentrator.</p>
<p>How much does it cost to get a small <strong>oxygen</strong> tank (and to have it filled) from a welding supply?</p>
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<h3>admin answers:</h3>
<p class="dtm-content">£78.50</p>
<p>well actually there are different prices. The prices vary depending on your location and needs. Contact your local medical supply store.</p>
<p>For more info visit this website http://www.wetcanvas.com/forums/archive/index.php/t-175076.html</p>
<p>there are conversation on how much the oxygen tank costs and it will be helpful,,, good luck. Hope i help.</p>
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<p class="name">Mary asks…</p>
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<h2>Can lack of oxygen at birth cause developmental delays?</h2>
<p>My son had lack of <strong>oxygen</strong> and need <strong>oxygen</strong> of two days, now he is 4 and has issues.Does anyone have experience with this. Has your kid got better with <strong>therapy</strong>?</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Yes, a lack of oxygen at birth can cause developmental delays or cerebral palsy &#8211; as well as other problems.  My son had a complicated birth and spent some time in NICU.  He has PDD-NOS and Sensory Integration Dysfunction, he also has developmental delays in a few areas.  Therapy can help.  If you cannot afford therapy, or find it difficult to get there (working parents, therapy only during the day) &#8212;  try to go to at least a few appointments and learn what you can do at home.  Good luck!</p>
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		<title>Your Questions About H2o2 Decomposition</title>
		<link>http://www.answers-h2o2.com/226/your-questions-about-h2o2-decomposition-20/</link>
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		<pubDate>Tue, 17 Apr 2012 09:17:02 +0000</pubDate>
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		<description><![CDATA[George asks… GAS STOICHIOMETRY PROBLEM: 1) Consider the decomposition of hydrogen peroxide (H2O2) as represented by:? 2 H2O2(l) 2 H2O(g) + O2(g) (a) The coefficients in this balanced chemical equation represent the _____ of reactants and products involved in the &#8230; <a href="http://www.answers-h2o2.com/226/your-questions-about-h2o2-decomposition-20/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<p class="name">George asks…</p>
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<h2>GAS STOICHIOMETRY PROBLEM: 1) Consider the decomposition of hydrogen peroxide (H2O2) as represented by:?</h2>
<p>2 <strong>H2O2</strong>(l) 2 H2O(g) + O2(g)</p>
<p>(a) The coefficients in this balanced chemical equation represent the _____ of reactants and products involved in the chemical reaction. Select all that apply.<br />
-weights<br />
-masses<br />
-molecules<br />
-moles</p>
<p>(b) If 6.0 moles of hydrogen peroxide decompose, then____ moles of O2 will be produced.</p>
<p>(c) If 6.0 moles of hydrogen peroxide decompose, then____ grams of O2 will be produced.</p>
<p>2) Given the information above, what additional information must be known to determine the volume of oxygen that are produced when 6.0 moles of hydrogen peroxide decompose? Choose two.</p>
<p>a) molar mass of <strong>H2O2</strong><br />
b) molar mass of O2<br />
c) pressure<br />
d) temperature</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Moles</p>
<p>3.0 moles of O2</p>
<p>3.0 x 32 g/mol=96.0 g of O2</p>
<p>pressure and temperature</p>
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<p class="name">Chris asks…</p>
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<h2>H2O2+MnO2= What is the decomposition reaction??</h2>
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<h3>admin answers:</h3>
<p class="dtm-content">In this case MnO2 is a catalyst is not &#8220;consumed&#8221; in the reaction, which is essentially the decomposition of H2O2 into oxygen gas and water.</p>
<p>2H2O2 &#8212;MnO2&#8212;&gt;  2H2O + O2</p>
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		<title>Your Questions About Oxidation Numbers Compound H2o2</title>
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		<pubDate>Mon, 16 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Mark asks… I think this Oxidation-Reduction Reaction may be written incorrectly? It&#8217;s on a worksheet for an 11th grade Chemistry class. Can you try to oxidize and reduce it to see if it is written incorrectly? The numbers are subscripts. &#8230; <a href="http://www.answers-h2o2.com/225/your-questions-about-oxidation-numbers-compound-h2o2-2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<p class="name">Mark asks…</p>
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<h2>I think this Oxidation-Reduction Reaction may be written incorrectly?</h2>
<p>It&#8217;s on a worksheet for an 11th grade Chemistry class. Can you try to oxidize and reduce it to see if it is written incorrectly? The <strong>numbers</strong> are subscripts.</p>
<p>Na2Cr2O7 + HNO3 + <strong>H2O2</strong> &#8211;&gt; H3CrO8 + NaNO3 + H2O</p>
<p>Also, I&#8217;m aware that at least one of those compounds does not exist. Try solving the problem with the given compounds (if possible).</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Na2Cr2O7 &#8230;..(2 Cr+6each)&#8211;&gt;   H3CrO8 &#8230;(Cr+13) &#8230;.14 e- lost</p>
<p> H2O2    (2 O&#8217;s @ -1 each)&#8211;&gt;    H2O&#8230;(O-2) &#8230;.2 e- taken<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-<br />
to balance the e- taken &amp; lost:</p>
<p>1 Na2Cr2O7 + HNO3 + 7 H2O2 &#8211;&gt; H3CrO8 + NaNO3 + H2O</p>
<p>to balance the sodiums &amp; chromiums:</p>
<p>1Na2Cr2O7 + HNO3 + 7H2O2 &#8211;&gt; 2H3CrO8 +2 NaNO3 + H2O</p>
<p>to balance the nitrates:</p>
<p>1Na2Cr2O7 +2 HNO3 + 7H2O2 &#8211;&gt; 2H3CrO8 +2 NaNO3 + H2O</p>
<p>to balance the hydrogens:</p>
<p>1Na2Cr2O7 +2 HNO3 + 7H2O2 &#8211;&gt; 2H3CrO8 +2 NaNO3 + 5H2O</p>
<p>oxygens balance, as the check on the work&#8230; It&#8217;s done</p>
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<p class="name">Mary asks…</p>
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<h2>HW HELP PLSSSSS! Chemistry sucks <img src='http://www.answers-h2o2.com/wp-includes/images/smilies/icon_sad.gif' alt=':(' class='wp-smiley' /> ?</h2>
<p>16) name each of the binary molecular compounds in item 11 using the stock system.</p>
<p>26) name each of the following ionic compounds using the Stock system:<br />
a. NaCl<br />
b. KF<br />
c. CaS<br />
d. CO(NO3)2<br />
e. FePO4<br />
f. Hg2SO4<br />
g. Hg3(PO4)2</p>
<p>48) assign <strong>oxidation</strong> <strong>numbers</strong> to each atom in the following molecules and ions:<br />
a. CO2<br />
b. NH^+4<br />
c. MnO^-4<br />
d. S2O^-2 3<br />
e. <strong>H2O2</strong><br />
f. P4O10<br />
g. OF2</p>
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<h3>admin answers:</h3>
<p class="dtm-content">16) since i dont know the molecules of item 11 i cant answer that</p>
<p>26) type it in wikipedia and you have the answer(and additional infos)<br />
or just calculate the oxidation number of the kation (always the metal, the first element in the formula)</p>
<p>PS: stock was a nazi</p>
<p>48) consider following rules:<br />
F is always -1<br />
H is always +1 unless its paired with a metal than its -1<br />
O is always -2 unless it&#8217;s in a peroxide than its -1<br />
Metals have always positive oxidation numbers<br />
the sum off all oxidation numbers always correspond to the charge of the molecule/ion</p>
<p>e.g. MnO4- since O is -2 and there are 4 of them Mn has to be +7 and the sum is -1</p>
<p>PS: oxidation numbers are always written in roman numerals</p>
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		<title>Your Questions About Kmno4 H2o2 Oxidation Numbers</title>
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		<pubDate>Sun, 15 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Lisa asks… Plz help explaining reduction/ oxidation agents? actually, i understand the basics like oxidizing aagents get reduced themselves and oxidize others. but i dont understand something in my teacher&#8217;s notes&#8230; it says for oxidizing agents: oxidizing agents contain atoms &#8230; <a href="http://www.answers-h2o2.com/224/your-questions-about-kmno4-h2o2-oxidation-numbers-2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>Plz help explaining reduction/ oxidation agents?</h2>
<p>actually, i understand the basics like oxidizing aagents get reduced themselves and oxidize others. but i dont understand something in my teacher&#8217;s notes&#8230; it says for oxidizing agents:<br />
oxidizing agents contain atoms with high <strong>oxidation</strong> <strong>numbers</strong> *<br />
when they oxidize other substances they gain electrons.<br />
examples<br />
<strong>KMnO4</strong> (aq) (potassium permanganate), Cl2 (aq), <strong>H2O2</strong> (hydrogen peroxide), KCr2O7 (potassium Dichromate (VI))<br />
Potassium permanganate purple to colorless, potassium dichromate orange to green.**<br />
OK so the questions are:<br />
*how come??? dont they have atoms with high <strong>oxidation</strong> nums and then some with lower <strong>oxidation</strong> <strong>numbers</strong>? eg it says that hydrogen peroxide is an oxidizing agent&#8230; H+ O 2- ?dont all compounds and molecules like <strong>H2O2</strong> have all the <strong>oxidation</strong> <strong>numbers</strong> in them added to 0? so cant they be both oxidizing and reducing agents?<br />
**what are the color changes???<br />
hey thanx a lot to the guy who called me smart <img src='http://www.answers-h2o2.com/wp-includes/images/smilies/icon_biggrin.gif' alt=':D' class='wp-smiley' />  i hav 137 IQ and im 14&#8230; and u made me understand&#8230; thanx alottt<br />
hey thanx a lot to the guy who called me smart <img src='http://www.answers-h2o2.com/wp-includes/images/smilies/icon_biggrin.gif' alt=':D' class='wp-smiley' />  i hav 137 IQ and im 14&#8230; and u made me understand&#8230; thanx alottt</p>
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<h3>admin answers:</h3>
<p class="dtm-content">If u write a balanced  reaction and mark the oxidation state of each element individually in the compound , both the sides of the reaction u will see that net charge is conserved but on particular element oxidation state will vary<br />
when oxidation no. Increases it is oxidized and when o. No decreases it is reduced .<br />
  Color change depends on compound formed</p>
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<p class="name">Nancy asks…</p>
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<h2>**more chemitsry questions!!**?</h2>
<p>1) Given:<br />
2 MnO4- + 5 <strong>H2O2</strong> + 6 H+2 Mn+2 + 8 H2O + 5 O2</p>
<p>What volume of a 0.150M <strong>KMnO4</strong> solution would be needed to titrate 75.0mL of a 0.150M <strong>H2O2</strong> solution?<br />
  45.0 mL<br />
 75.0 mL<br />
 15.0 mL<br />
 30.0 mL<br />
 none of these  </p>
<p>2)Which one of the following is a redox reaction?<br />
  H+ (aq) + OH- (aq)3H2 + AlCl3<br />
 CO32- (aq) + HSO4- (aqHCO3- (aq) + SO42- (aq)<br />
 2KBr(aq) + Pb(NO3)2 (aq) 2KNO3 (aq) + PbBr2 (s)<br />
 CaBr2 (aq) + H2SO4 (aq)CaSO4 (s) + 2HBr(g)<br />
 2Al(s) + 3H2SO4 (aq) Al2(SO4)3 (aq) + 3H2 (g)  </p>
<p>3) What are the respective <strong>oxidation</strong> <strong>numbers</strong> of sulfur in the thiosulfate ion (S2O32-) and the tetrathionate ion (S4O62-)?<br />
  -2, -2.5<br />
 +2, +2.5<br />
 +0.5, +1<br />
 +3, +3<br />
 -0.5, -1  </p>
<p>4)  What volume of 12.0M nitric acid is required to prepare 6.00 L of 0.100 M nitric acid?<br />
  0.05 L<br />
 0.50 L<br />
 1.0 L<br />
 0.02 L<br />
 1.20 L </p>
<p>5)  The electron dot formula for AsCl3 shows:<br />
  two single bonds, one double bond, and 9 lone pairs<br />
 a total of 84 electron dots<br />
 one single bond, two double bonds, and 8 lone pairs<br />
 three single bonds and 10 lone pairs<br />
 three single bonds and one lone pair</p>
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<h3>admin answers:</h3>
<p class="dtm-content">WHAT???</p>
<p>MORE &#8216;homework&#8217; that YOU didn&#8217;t DO!</p>
<p>And NOT just in &#8220;chemitsry&#8221;!</p>
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		<title>Your Questions About Kmno4 H2o2 Oxidation Numbers</title>
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		<pubDate>Sat, 14 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Mandy asks… Oxidation numbers? i need to find the oxidation numbers for all of the atoms in the following equations: Cu + HNO3 &#8212;&#62; CuNO3 + H2 KMnO4 + H2O2 &#8212;&#62; KOH + MnO2 + O2 i believe these equations &#8230; <a href="http://www.answers-h2o2.com/223/your-questions-about-kmno4-h2o2-oxidation-numbers/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>Oxidation numbers?</h2>
<p>i need to find the <strong>oxidation</strong> <strong>numbers</strong> for all of the atoms in the following equations:</p>
<p>Cu + HNO3 &#8212;&gt; CuNO3 + H2</p>
<p><strong>KMnO4</strong> + <strong>H2O2</strong> &#8212;&gt; KOH + MnO2 + O2</p>
<p>i believe these equations are correct however any corrections would be greatly appreciated.</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Cu + 2HNO3 ==&gt; Cu(NO3)2 + H2<br />
Cu &#8211; oxidation number 0<br />
H &#8211; +1<br />
H2 = zero<br />
N +5 (both sides)<br />
O -2 (both sides)<br />
CuNO3 &#8211; Cu is +2</p>
<p>2KMnO4 + H2O2 ==&gt; 2KOH + 2MnO2 + 2O2<br />
K (both sides) +1<br />
H2O2<br />
    H is +1<br />
    O is -1<br />
H2O<br />
    H is +1<br />
    O is -2<br />
MnO4<br />
    Mn is +7<br />
    O is -2<br />
MnO2<br />
    Mn is +4<br />
    O is -2<br />
O2 &#8211; zero valent</p>
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<p class="name">Ken asks…</p>
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<h2>Assign oxidation numbers to all elements in each compound or ion below:?</h2>
<p>1.HCl<br />
2.KNO3<br />
3.OH-<br />
4.Mg3N2<br />
5.KClO3<br />
6.Al(NO3)3<br />
7.S8<br />
8.<strong>H2O2</strong><br />
9.PbO2<br />
10.NaHSO4<br />
11.H2SO3<br />
12.H2SO4<br />
13.BaO2<br />
14.<strong>KMnO4</strong><br />
15.LiH<br />
16.MnO2<br />
17OF2<br />
18.SO3<br />
19.NH3<br />
20.Na</p>
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<h3>admin answers:</h3>
<p class="dtm-content">The rules are attached below</p>
<p>if the overall charge of the compund is neutral, using the rules, determine the element that is not yet determined</p>
<p>ex. Al(NO3)3, the overall charge is 0<br />
we know that, according to the compound, Al = 3+, NO3 = 1-<br />
so, we need to determine the charge of N<br />
NO3- has an overall charge of 1-, O is always 2- except in peroxides</p>
<p>(1N)(+x) + (3 O)(-2) = -1<br />
x = 5+ so N = 5+</p>
<p>for binary ionic compounds, the charges on the elements are equal to the subscript of the other element.  Mg3N2: Mg 2+, N 3-</p>
<p>for covalent compounds, follow the rules<br />
OF2, F is ALWAYS 1-, the overall charge = 0<br />
(O)(+x) + (2F)(-1) = 0<br />
x = 2, O = 2+<br />
SO3 = covalent compound, O is  2- and there are 3 of them for -6.  The over all charge is 0<br />
S = 6+</p>
<p>H2O2 is peroxide and O is 1- in peroxides</p>
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		<title>Your Questions About H2o2 Oxidation Number H</title>
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		<pubDate>Fri, 13 Apr 2012 09:17:02 +0000</pubDate>
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		<description><![CDATA[Paul asks… HELP PLEASE, chemistry questions? Please, and THANK YOU SO MUCH in advance. Find the oxidation number for: O in H2O2 Ca in Ca(OH)2 O in O2- Rb in Rb+ Fe in Fe(s) O in OF Cl in CaCl2 &#8230; <a href="http://www.answers-h2o2.com/222/your-questions-about-h2o2-oxidation-number-h/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>HELP PLEASE, chemistry questions?</h2>
<p>Please, and THANK YOU SO MUCH in advance.</p>
<p>Find the <strong>oxidation</strong> <strong>number</strong> for:</p>
<p>O in <strong>H2O2</strong></p>
<p>Ca in Ca(OH)2</p>
<p>O in O2-</p>
<p>Rb in Rb+</p>
<p>Fe in Fe(s)</p>
<p>O in OF</p>
<p>Cl in CaCl2</p>
<p><strong>H</strong> in KH</p>
<p>F in LiF</p>
<p>N in N2</p>
<p>I didn&#8217;t learn this, and I need assistance badly.</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Http://www.kentchemistry.com/links/Redox/oxnumbers.htm</p>
<p>follow these rules and you will be fine</p>
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<p class="name">Sharon asks…</p>
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<h2>5 Electrochemistry questions&#8230;?</h2>
<p>1. Cr2O7^2- + 6I^- + 14 <strong>H</strong>^+ &#8211;&gt; 2Cr^3+ + 3I2 + 7H2O<br />
Which of the following statements about the reaction given above is NOT true?<br />
A) The <strong>oxidation</strong> <strong>number</strong> of chromium changes from +6 to +3.<br />
B) The <strong>oxidation</strong> <strong>number</strong> of iodine changes from -1 to 0.<br />
C) The <strong>oxidation</strong> <strong>number</strong> of hydrogen changes from + 1 to 0.<br />
D) The <strong>oxidation</strong> <strong>number</strong> of oxygen remains the same.<br />
E) The reaction takes place in acidic solution.</p>
<p>2. Al^3+ + 3e^- &#8211;&gt; AI(s)<br />
Eº = -1.66 V<br />
Cr^3+ + 3e^- &#8211;&gt; Cr(s)<br />
Eº = -0.74 V<br />
The standard reduction potentials for two half-reactions are shown above. Which of the statements listed below will be true for the following reaction taking place under standard conditions?<br />
AI(s) + Cr^3+ &#8211;&gt; Al^3+ + Cr(s)<br />
A) Eº = 2.40 V, and the reaction is not spontaneous.<br />
B) Eº = 0.92 V, and the reaction is spontaneous.<br />
C) Eº = -0.92 V, and the reaction is not spontaneous.<br />
D) Eº = -0.92 V, and the reaction is spontaneous.<br />
E) Eº = -2.40 V, and the reaction is not spontaneous.</p>
<p>3.In which of the following molecules does hydrogen have an <strong>oxidation</strong> state of -1?<br />
A) HP<br />
B) NH3<br />
C) CaH2<br />
D) CH4<br />
E) H2</p>
<p>4.The equation for the decomposition of <strong>H2O2</strong> is shown below.<br />
2H2O2 &#8211;&gt; 2H2 + O2<br />
Which of the following statements about the reaction shown above is true?<br />
A) Oxygen is reduced, and hydrogen is oxidized.<br />
B) Oxygen is oxidized, and hydrogen is reduced.<br />
C) Oxygen is both oxidized and reduced.<br />
D) Hydrogen is both oxidized and reduced.<br />
E) Neither oxygen nor hydrogen change <strong>oxidation</strong> state.</p>
<p>5.When solid iron is brought into contact with water and oxygen, it undergoes the following half-reaction:<br />
Fe(s) &#8211;&gt; Fe^2+(aq)<br />
This half-reaction is instrumental in the corrosion of iron. When iron is coated with solid zinc, the half-reaction above is impeded, even if the zinc coating is incomplete. This is most likely because<br />
A) Zn(s) is more easily reduced than Fe(s).<br />
B) Zn(s) is more easily oxidized than Fe(s).<br />
C) Zn^2+(aq) is more easily reduced than Fe(s).<br />
D) Zn^2+(aq) is more easily oxidized than Fe(s).<br />
E) Zn(s) is more easily reduced than Fe^2+(aq).</p>
<p>Thank you for helping me!!! I really do appreciate it! If it won&#8217;t steal your time too much, could you explain these and how you got the answers too? Thanks! <img src='http://www.answers-h2o2.com/wp-includes/images/smilies/icon_biggrin.gif' alt=':D' class='wp-smiley' /> </p>
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<h3>admin answers:</h3>
<p class="dtm-content">Hi Angie,</p>
<p>1. Cr2O7^2- + 6I^- + 14 H^+ &#8211;&gt; 2Cr^3+ + 3I2 + 7H2O<br />
Which of the following statements about the reaction given above is NOT true ?<br />
¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯<br />
C) The oxidation number of hydrogen changes from + 1 to 0. . . . NOT TRUE</p>
<p>2. Al^3+ + 3e^- &#8211;&gt; AI(s)<br />
Eº = -1.66 V<br />
Cr^3+ + 3e^- &#8211;&gt; Cr(s)<br />
Eº = -0.74 V<br />
The standard reduction potentials for two half-reactions are shown above. Which of the statements listed below will be true for the following reaction taking place under standard conditions?<br />
¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯<br />
B) Eº = 0.92 V, and the reaction is spontaneous. . . . . .TRUE</p>
<p>3.In which of the following molecules does hydrogen have an oxidation state of -1?<br />
¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯<br />
A) HP</p>
<p>4.The equation for the decomposition of H2O2 is shown below.<br />
2H2O2 &#8211;&gt; 2H2 + O2<br />
Which of the following statements about the reaction shown above is true?<br />
¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯<br />
B) Oxygen is oxidized, and hydrogen is reduced.</p>
<p>5.When solid iron is brought into contact with water and oxygen, it undergoes the following half-reaction:<br />
Fe(s) &#8211;&gt; Fe^2+(aq)<br />
This half-reaction is instrumental in the corrosion of iron. When iron is coated with solid zinc, the half-reaction above is impeded, even if the zinc coating is incomplete. This is most likely because<br />
¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯¯ ¯¯¯¯¯¯¯¯¯<br />
B) Zn(s) is more easily oxidized than Fe(s).</p>
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		<title>Your Questions About Oxidation Numbers Compound H2o2</title>
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		<pubDate>Thu, 12 Apr 2012 09:17:02 +0000</pubDate>
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		<description><![CDATA[Chris asks… Can someone help assign oxidation numbers to the following compounds? Does anyone want to help assign oxidation numbers to the following? H2O H2O2 Na2O NaO2 K2Cr2O7 (MnO4)- (Fe)3 Cl2 OF2 HCN N2H4 (S2O3)2- admin answers: First some general &#8230; <a href="http://www.answers-h2o2.com/221/your-questions-about-oxidation-numbers-compound-h2o2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>Can someone help assign oxidation numbers to the following compounds?</h2>
<p>Does anyone want to help assign <strong>oxidation</strong> <strong>numbers</strong> to the following?</p>
<p>H2O<br />
<strong>H2O2</strong><br />
Na2O<br />
NaO2<br />
K2Cr2O7<br />
(MnO4)-<br />
(Fe)3<br />
Cl2<br />
OF2<br />
HCN<br />
N2H4<br />
(S2O3)2-</p>
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<h3>admin answers:</h3>
<p class="dtm-content">First some general guidelines.  Oxygen always gets to be -2 (unless it&#8217;s a peroxide &#8211; as in H2O2-, and then it&#8217;s -1).  Hydrogen is always +1 (unless its a hydride &#8211; comes second &#8211; and then it&#8217;s -1).  The oxidation number is the same as the ionic charge.  </p>
<p>The oxidation number of an element in the elemental state (even diatomic or triatomic molecule, as Cl2 or O3) is zero.</p>
<p>The sum of the oxidation numbers will always be zero for a compound or the charge on a polyatomic ion.</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-</p>
<p>Pandra got most of these, but there are a couple that need tweaking.</p>
<p>H2O -&gt; H = +1, 0 = -2, OK<br />
H2O2 -&gt; H = +2, O = -2, NO, H=+1, O=-1 (peroxide)<br />
Na2O -&gt; Na = +1, O = -2; OK<br />
NaO2 -&gt; Na = +4, O = -2, No, Na=+1, O= 1/2 (superoxide)<br />
K2Cr2O7 -&gt; K = +2, Cr = +5, O = -2, NO, K=+1, Cr=+6<br />
MnO4 -&gt; Mn = +8, O = -2, NO this is an ion, Mn = +7<br />
(Fe)3 -&gt; Fe = +3 If this is just Iron (Never heard of Fe3) it is 0<br />
Cl2 -&gt; Cl = -1, NO, Cl=0, it&#8217;s elemental<br />
OF2 -&gt; O = +2, F = -1, OK (this is the only compound where O has a positive oxidation number.)<br />
HCN -&gt; H = +1, C = -4, N = -3, NO (there&#8217;s no way this adds up to zero.  H = +1, C = +2, N= -3<br />
N2H4 -&gt; N = -2, H = + 1, Or you could do N=+2, H=-1 if you consider this a hydride.<br />
(S2O3)2- -&gt; S = +2, O = -2 , plus e2-, NO &#8211; this is an ion.  S = +4, O = -2.</p>
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<p class="name">Mary asks…</p>
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<h2>What are the oxidation numbers for the elements in these compounds?</h2>
<p>What are the <strong>oxidation</strong> <strong>numbers</strong> for the elements in the compounds below:</p>
<p>1) H2O</p>
<p>2) <strong>H2O2</strong></p>
<p>3) ClO3-</p>
<p>4) Pb3(PO4)4</p>
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<h3>admin answers:</h3>
<p class="dtm-content">Rule of thumb: H is nearly always 1+ and O is most of the time 2- (but there are exceptions! See #2)</p>
<p>1) H is 1+ but you have 2 of them, so 2+ total.<br />
   O is always 2-.</p>
<p>2) H is 1+ but you have 2 of them, so that&#8217;s 2+ total. O, however, cannot be 2- this time since this molecule is neutral. O must have a 1- charge; you have 2 of them, so 2- total.</p>
<p>3) O is 2-, but you have 3 of them, so 6-. Cl must be 5+ in order to make the -1 charge.</p>
<p>4) PO4 (phosphate) has a 3- charge, with 4 of them that means it&#8217;s 12- total. That means Lead (Pb) must be 4+ to cancel out the 12- (since there are 3 leads).</p>
<p>Inside phosphate itself, oxygen is 2- x 4 x 4 = 16-. P is 4+ x 4 = +16.</p>
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		<title>Your Questions About Oxygen Therapy</title>
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		<pubDate>Wed, 11 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Nancy asks… Hyperbaric oxygen treatment for Lyme disease? I&#8217;ve heard about hyperbaric oxygen treatment as a therapy for Lyme disease? Has anyone else with Lyme tried this or knows someone who has? admin answers: Though I haven&#8217;t tried it, I &#8230; <a href="http://www.answers-h2o2.com/220/your-questions-about-oxygen-therapy-49/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>Hyperbaric oxygen treatment for Lyme disease?</h2>
<p>I&#8217;ve heard about hyperbaric <strong>oxygen</strong> treatment as a <strong>therapy</strong> for Lyme disease?  Has anyone else with Lyme tried this or knows someone who has?</p>
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<p class="dtm-content">Though I haven&#8217;t tried it, I do know of someone who maintains she benefited from it. Supposedly the borrelia are susceptible to higher-than-normal oxygen concentrations in the tissue. This would make sense with Lyme as it is an anaerobic bacteria.<br />
But I wouldn&#8217;t spend too much time pursuing it as it can be difficult &amp; expensive to arrange.<br />
Lyme-literate doctors&#8217; experience has shown that exercise every other day for an hour or more (not aerobic, just to get the pulse up) works quite well in fighting the disease (esp. While ON antibiotics) thru oxygenation of the blood, increased [body] core temperature &amp; better outer capillary blood flow.  And it&#8217;s a heck of a lot cheaper!</p>
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<h2>How can oxygen in the body influence a cell&#8217;s polarity and a field or its gravitational forces in the body?</h2>
<p>Hyperoxigenation <strong>therapy</strong> has to do with medicine (it is an alternative treatment where one is administered high doses of intravenous O2 &#8211; i think in the form of o3). Since the body operates on biophysics, there must be an association between <strong>oxygen</strong> and how it can alter magnetic fields, gravitational forces and such, which then helps to explain part of the <strong>therapy</strong>&#8216;s success still unrecognized. On the long run, this is to illustrate myself and others the importance of breathing and how the lack of it can lead to a disrupted cell environment and communication (in terms of its &#8220;field&#8221;). Any hints or references please.</p>
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<p class="dtm-content">Man I wish i knew what you just said.</p>
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		<title>Your Questions About H2o2 Oxidation Number</title>
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		<pubDate>Tue, 10 Apr 2012 09:17:03 +0000</pubDate>
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		<description><![CDATA[Paul asks… Need help with two chemistry question? In which compound is the oxidation number of oxygen -1? 1)CO 2)CO2 3)H2O 4) H2O2 Oxygen will have a positive oxidation number when combined with 1) F 2) Cl 3) Bromine 4) &#8230; <a href="http://www.answers-h2o2.com/219/your-questions-about-h2o2-oxidation-number-19/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<h2>Need help with two chemistry question?</h2>
<p>In which compound is the <strong>oxidation</strong> <strong>number</strong> of oxygen -1?<br />
1)CO  2)CO2  3)H2O  4) <strong>H2O2</strong></p>
<p>Oxygen will have a positive <strong>oxidation</strong> <strong>number</strong> when combined with<br />
1) F  2) Cl  3) Bromine 4) Iodine</p>
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<h3>admin answers:</h3>
<p class="dtm-content">H2O2 ( it is a peroxide)</p>
<p>F ( because F is more electronegative )</p>
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<h2>Can someone check these ten questions and tell me how to do the ones I missed. Really struggled with these.?</h2>
<p>2) State the <strong>oxidation</strong> <strong>number</strong> for each of the following nonmetals.<br />
a) H2<br />
b) He<br />
c) P4<br />
d) I2<br />
a) 0<br />
b) 0<br />
c) 0<br />
d) 0</p>
<p>10) Supply the term that corresponds to each of the following.<br />
a) a substance that increases its <strong>oxidation</strong> <strong>number</strong> in a redox reaction<br />
b) a substance that decreases its <strong>oxidation</strong> <strong>number</strong> in a redox reaction<br />
a) Oxidizing agent<br />
b) Reducing agent</p>
<p>14) Indicate the oxidizing and reducing agents in the following redox reactions.<br />
a) Ca(s) + 2 H2O(l) ? Ca(OH)2(aq) + H2(g)<br />
b) Mg(s) + 2 HCl(aq) ? MgCl2(aq) + H2(g)<br />
a) Ca is the reducing agent and H2 is the oxidizing agent<br />
b) Mg is the reducing agent and H2 is the oxidizing agent</p>
<p>24) Write a balanced equation for each of the following redox reactions using the <strong>oxidation</strong> <strong>number</strong> method.<br />
a) Fe2+(aq) + <strong>H2O2</strong>(aq) + H+(aq) ? Fe3+(aq) + H2O(l)<br />
b) Cr2O72-(aq) + Br-(aq) + H+(aq) ? Cr3+(aq) +  Br2(l) +  H2O(l)<br />
a) 2 Fe2+(aq) + <strong>H2O2</strong>(aq) + 2 H+(aq) ? 2 Fe3+(aq) + 2 H2O(l)<br />
b) Cr2O72-(aq) + 6 Br-(aq) + 14 H+(aq) ? 2 Cr3+(aq) + 3 Br2(l) + 7 H2O(l)</p>
<p>36) Sulfur can undergo a redox reaction in which it is simultaneously oxidized and reduced.  Write a balanced equation for the following in a basic solution.<br />
S(s) ? SO32-(aq) + S2-(aq)<br />
3 S(s) + 6 OH- ? SO32-(aq) + 2 S2-(aq) + 3 H2O(l)</p>
<p>40) Refer to Table 17.3 and indicate which substance in each of the following pairs is the stronger reducing agent.<br />
a) Cu(s) or Cr(s)<br />
b) H2(g) or Cu(s)<br />
c) Cu(s) or I-(aq)<br />
d) Cl-(aq) or H2(g)<br />
a) Cr(s)<br />
b) H2(g)<br />
c) Cu</p>
<p>54) The spontaneous redox reaction of hydrogen gas and iodine occurs according to the following equation.<br />
H2(g) + I2(s) ? 2 H+(aq) + 2 I-(aq)<br />
Assume the half-reactions are separated into two compartments.  A hydrogen gas Pt electrode is immersed in 1.00 M HI, and a second Pt electrode is placed in 1.00 M KI-I2 solution.  Indicate each of the following in this voltaic cell.<br />
a) <strong>oxidation</strong> half-cell reaction<br />
b) reduction half-cell reaction<br />
c) anode and cathode<br />
d) direction of electron flow<br />
e) direction of I- in the salt bridge<br />
a) H2 ?  H+ + 1 e-<br />
b) I2 + 1 e- ? I-<br />
c) H2 is the anode because it is where the <strong>oxidation</strong> occurs and I2 is the cathode because it is where reduction occurs.<br />
d) Electrons flow from H2 anode to I2 cathode<br />
e) I- flow from the I2 cathode towards the H2 anode</p>
<p>60) The nonspontaneous redox reaction of lead and zinc nitrate solution occurs according to the following ionic equation.<br />
Pb(s) + Zn2+(aq) ? Zn(s) + Pb2+(aq)<br />
Assume the half-reactions are separated into two compartments.  A zinc electrode is immersed in 1.00 M , Zn(NO3)2 and a lead electrode in 1.00 M Pb(NO3)2.  Indicate each of the following in this electolytic cell.<br />
a) <strong>oxidation</strong> half-cell reaction<br />
b) reduction half-cell reaction<br />
c) anode and cathode<br />
d) direction of electron flow<br />
e) direction of NO3- in the salt bridge<br />
a) Pb ? Pb2+ + 2 e-<br />
b) Zn2+ + 2 e- ? Zn<br />
c) Pb is the anode and Zn is the cathode<br />
d) Electrons flow from Pb anode to Zn cathode<br />
e) NO3- flows from the Zn cathode towards the Pb anode</p>
<p>66) The redox reaction between liguid mercury and aqueous gold(III) acetate produces mercury(I) acetate and gold metal.  Write a net ionic equation for this reaction.<br />
3 Hg(l) + 2 Au(O2CCH3)3(aq)  ? 3 Hg(O2CCH3)2(aq) + 2 Au(s)</p>
<p>70) Write a balanced equation for the reaction of ethyl alcohol, C2H5OH, and acidic potassium dichromate solution.<br />
 C2H5OH(aq) + Cr2O72-(aq) ? HC2H3O2(aq) + Cr3+(aq) + H2O(l)<br />
3 C2H5OH(aq) + 2 Cr2O72-(aq) + 16 H+ ? 3 HC2H3O2(aq) + 4 Cr3+(aq) + 11 H2O(l)</p>
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<h3>admin answers:</h3>
<p class="dtm-content">2) These are right </p>
<p>10) Be careful wiht this one. If a substance increases its oxidation number, then it<br />
is LOSING electrons because electrons are negative. Check out this example: </p>
<p>Mg + O &#8212;&gt; MgO<br />
The oxidation # of Mg increases, going from 0 to 2+; therefore it lost<br />
electrons. If it lost electrons it was oxidized, but that means it is the<br />
reducing agent. So you have the two answers reversed. This is always confusing<br />
for people. Try to remember LEO goes GER; lose electrons oxidized; gain<br />
electrons reduced; then the opposite for naming the agents (reducing and<br />
oxidizing respectively) </p>
<p>Note that if you are adding electrons to a compound, its ox# will get more and<br />
more negative, which means it is getting smaller and smaller. So if the ox# is<br />
decreasing it is gaining electrons and teh oxidizing agent. </p>
<p>14) Good job! These are right. </p>
<p>24) I can&#8217;t remember what the oxidation number method is. I think you ust have to<br />
make sure the charges are balanced too. This looks right to me, but honestly I<br />
am not positive. I need to do some review! </p>
<p>36) Looks good to me. </p>
<p>40)<br />
I don&#8217;t have a table with me, so I am not postive, but these look right by first<br />
glance.<br />
For D I think it would be the H2, but again, I don&#8217;t have a table with me, so<br />
double check it. </p>
<p>54) Good! Looks right. </p>
<p>60) Perfect! </p>
<p>66) For this they are looking for the net ionic equation, so just put the reaction<br />
that occurs between the ions. So split Au(O2CCH3)3 and Hg(O2CCH3)2  into their<br />
ions and only include the ions that change in oxidation number for the equation<br />
I think. </p>
<p>70) i think this is okay too. </p>
<p>You did a great job! It seems like you have a good understanding of electrochem.<br />
Don&#8217;t be too discouraged about struggling with these. I tutor college chemistry<br />
and electrochem is hard for a lot people.<br />
I hope this helped.</p>
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